We have
TR1(y1) = y1(20 2y1) TR2(y2) = y2(16 y2/2)and hence
MR1(y1) = 20 4y1 MR2(y2) = 16 y2.
Thus the condition MR1(y1*) = MR2(y2*) = MC(y1* + y2*) is equivalent to
20 4y1* = 16 y2* = 2(y1* + y2*).Isolating y2* in the first equation we obtain
y2* = 4y1* 4.Plugging this into the expression 20 4y1* = 2(y1* + y2*) we obtain
20 4y1* = 2(y1* + 4y1* 4)or
28 = 14y1*or
y1* = 2,so that
y2* = 4.(I am assuming that the first-order conditions identify a maximum rather than a minimum.)